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For a dilute solution containing 2.5 g o...

For a dilute solution containing `2.5 g` of a non-volatile non-electrolyte solute in `100 g` of water, the elevation in boiling point at `1 atm` pressure is `2^(@)C`. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (`mm` of `Hg`) of the solution is (take `K_(b)=0.76 K kg mol^(-1)`)

A

724

B

740

C

736

D

718

Text Solution

Verified by Experts

`DeltaT_(f)=iK_(b)m` (`i=1` for non -electrolyte)`implies2.0.76xxn/(100/1000)impliesn=2/7.6`
Relative lowering in vapour pressure `=chi_(B)` (mole fraction of solute).
For dilute solution we can assume `(Deltap)/(PÅ)=(n_("solute"))/(n_("solvent"))`
`implies(DeltaP)/(p_(A)^(@))=(2//7.6)/(100//18)implies(DeltaP)/760=36/760impliesDelta=36impliesP=724`mm
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