The mole fraction of a solute in a solution is 0.1. At 298 K, molarity of this solution is the same as its molality. Density of this solution at 298 K is `2.0 g cm^(-3)`. The ratio of the molecular weights of the solute and solvent, `((MW_("solite"))/(MW_("solvent")))` is .........

Explanation

`m=(chi_(B)xx1000)/(chi_(A)xxM_(A))" "implies" "m=1000/(9M_(A))`…………I
Also using
`m=(1000M)/(1000d-MM_(B))" "implies" "MM_(B)=1000`…….ii
`1=1000/(1000xx2-MM_(B))`
Using i and ii : `(M_(B))/(M_(A))=9` (Molality = molarity)