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A galvanometer has a resistance of 20Ome...

A galvanometer has a resistance of `20Omega` and reads full-scale when `0.2V` is applied across it. To convert it into a `10A` ammeter, the galvanometer coil should have a

A

`0.01 Omega `resistor connected across it

B

`0.02 Omega `resistor connected across it

C

`200 Omega` resistor connected in series with it

D

`2000 Omega` resistor connected in series with it

Text Solution

AI Generated Solution

To convert the given galvanometer into a 10A ammeter, we need to determine the required shunt resistance that should be connected in parallel with the galvanometer. Here’s a step-by-step solution: ### Step 1: Identify the given values - Resistance of the galvanometer, \( R_G = 20 \, \Omega \) - Voltage at full scale, \( V = 0.2 \, V \) ### Step 2: Calculate the full-scale current through the galvanometer Using Ohm's law, we can calculate the current that corresponds to the full-scale deflection of the galvanometer: ...
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