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When a resistance of 100Omega is connect...

When a resistance of 100`Omega` is connected in series with a galvanometer of resistance R, then its range is V. To double its range, a resistance of 1000`Omega` is connected in series. Find the value of R.

A

`700 Omega`

B

`800 Omega`

C

`900 Omega`

D

`1000 Omega`

Text Solution

Verified by Experts

When resistance `100 Omega` is connected in series `i=V/(100+R)`………(i)
When resistance of `100Omega` is connected in series, then its range is double `i=(2V)/(1100+R)`…………(ii)
On solving (i) & (ii) ,we get `R=900 Omega`
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