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A potentiometer wire of length 1m and re...

A potentiometer wire of length 1m and resistance `20 Omega` is connected in series with a 15V battery and an external resistance `40 Omega` . A secondary cell of emf E in the secondary circuit is balanced by 24 cm long potentiometer wire. The emf E of the cell is ,

A

2.5V

B

1.2V

C

2.0V

D

3 V

Text Solution

AI Generated Solution

To solve the problem step by step, we will follow the given information and apply the relevant formulas. ### Step 1: Determine the total resistance in the circuit The total resistance \( R_{total} \) in the circuit is the sum of the resistance of the potentiometer wire and the external resistance. \[ R_{total} = R_{potentiometer} + R_{external} = 20 \, \Omega + 40 \, \Omega = 60 \, \Omega \] ...
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