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A 2 V battery, a 990Omega resistor and a...

A 2 V battery, a `990Omega` resistor and a potentiometer of 2 m length, all are connected in series of the resistance of potentiometer wire is `10Omega`, then the potential gradient of the potentiometer wire is

A

`0.05Vm^-1`

B

`0.5Vm^-1`

C

`0.01Vm^-1`

D

`0.1Vm^-1`

Text Solution

AI Generated Solution

To solve the problem step by step, we will calculate the potential gradient of the potentiometer wire connected in series with a battery and a resistor. ### Step 1: Identify the given values - Voltage of the battery (V) = 2 V - Resistance of the fixed resistor (R1) = 990 Ω - Resistance of the potentiometer wire (R2) = 10 Ω - Length of the potentiometer wire (L) = 2 m ...
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