A Wheatstone network consists of four resistances (in cyclic order) `10Omega,5Omega,6Omega,6Omega` . The resistance that must be connected across the `10Omega`resistance so that the network becomes balanced is (in Ohm):

Options

A. 10
B. 5
C. 20
D. 6

Explanation

To solve the problem of finding the resistance that must be connected across the 10Ω resistor in a Wheatstone network to make it balanced, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Wheatstone Bridge Configuration**:
The Wheatstone bridge consists of four resistors arranged in a diamond shape. The resistors are given as follows:
- R1 = 10Ω (across which we need to connect a resistor)
- R2 = 5Ω
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