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In the figure shown for given values of ...

In the figure shown for given values of `R_1` and `R_2` the balance point for Jockey is at `40cm` from `A`. When `R_2` is shunted by a resistance of `10Omega`, balance shifts to `50cm`. `R_1` and `R_2` are (`AB=1m`):

A

`10/5Omega,5Omega`

B

`20Omega,30Omega`

C

`10Omega,15Omega`

D

`5Omega,15/2Omega`

Text Solution

Verified by Experts

Initially `R_1/R_2=40/60`
When `R_2` is shunted by a `10Omega` resistance, its value becomes
`R_2=(10R_2)/(10+R_2)` Then,
Solving we get `R_1=10/3 Omega and R_2=5 Omega`
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