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For the circuit shown below: The cu...

For the circuit shown below:

The current through the

A

`3Omega`resistor is 0.5 A

B

`3Omega`resistor is 0.25 A

C

`4Omega`resistor is 0.5 A

D

`4Omega`resistor is 0.25 A

Text Solution

Verified by Experts

Net resistance of a circuit is So, current from cell `i=1/9=1 A` = current through `3Omega`
Potential difference between points A and B is `V_A-V_N=9-1(3+2)=4V=8i_2`
`therefore i_1=0.5A,i_2=1-o_1=0.5A`
Potential difference between C and D,
`V_C-V_D=(V_A-V_B)=i_2(2+2)`
`=4-4i_2=4-4 (0.5)=2V=8i_2`
`implies i_3=0.25A`
`implies i_4=i_2-i_3=0.5-0.25`
`therefore i_4=0.25A`
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