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For the given circuit, if internal resis...

For the given circuit, if internal resistance of cell is `1.5Omega` then`V_p-V_q` is equal to:

A

0

B

4V

C

`-4V`

D

`-2.5V`

Text Solution

Verified by Experts

`R_(eq)=5/2+1.5=4A`
Current through cell `=V/R=20/4=5A`
SO, current through each branch `=i/2=2.5A`
Now, considering loop
Now, applying Kirchhoff’s rule to part loop P to Q
`V_p-2 times 2.5+3 times 2.5=V_Q implies V_p-V_Q=-2.5V`

`V_(AB)=2 times 2.5+3 times 2.5=V_Q implies V_P-V_Q=-2.5V`
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