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The emf of a cell is epsilon and its int...

The emf of a cell is `epsilon` and its internal resistance is r. its terminals are connected to a resistance R. The potential difference between the terminals is `1.6V` for `R = 4 Omega`, and `1.8 V` for `R = 9 Omega`. Then,

A

E=1v r=`1Omega`

B

E=2v r=`1 Omega`

C

`E=2v,r=2Omega`

D

E=2.5V, `r=0.5 Omega`

Text Solution

AI Generated Solution

To solve the problem, we need to find the EMF (ε) of the cell and its internal resistance (r) based on the given terminal potential differences (V) for different external resistances (R). ### Step-by-Step Solution: 1. **Identify the Given Values:** - For R1 = 4 Ω, V1 = 1.6 V - For R2 = 9 Ω, V2 = 1.8 V ...
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