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n identical cells, each of emf epsilon a...

n identical cells, each of emf `epsilon` and internal resistance r, are joined in series to form a closed circuit. One cell A is joined with reversed polarity. The potential difference across any one cell is

A

`(2E)/n`

B

`(n-1)/n E`

C

`(n-2)/n E`

D

`(2n)/(n-2) E`

Text Solution

Verified by Experts

`r_0=r+r+….n time s =nr`
Net emf =`(n-1)E-E=(n-2)E`
`R_(eq)=nr`
Potential difference `V=E-ir=E-(((n-1)E)/(nr))r=(2E)/n`
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