Home
Class 12
PHYSICS
The moment of inertia of a door of mass ...

The moment of inertia of a door of mass `m`, length `2l` and width `l` about its longer side is

A

`(11 m I^(2))/24`

B

`(5m I^(2))/24`

C

`(mI^(2))/3`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

(about (YY')) `=(mI^(2))/12`
Using parallel axis theorem,
I(about AD) = `(mI^(2))/12 + (mI^(2))/4 = (mI^(2))/3`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise LEVEL - 1 (Angular Momentum, Collision)|15 Videos
  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise LEVEL - 1 (Mixed topics)|15 Videos
  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise LEVEL-0 (LA: Long Answer Type)|3 Videos
  • REVISION TEST-2 JEE

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos
  • SIMPLE HARMONIC MOTION

    VMC MODULES ENGLISH|Exercise 7-previous year question|46 Videos

Similar Questions

Explore conceptually related problems

The moment of inertia of a door of mass m , length 2 l and width l about its longer side is.

The moment of inertia of a uniform cylinder of length l and radius R about its perpendicular bisector is I . What is the ratio l//R such that the moment of inertia is minimum ?

In Fig. find moment of inertia of a plate having mass M , length l and width b about axes 1, 2, 3 and 4 . Assume that C is the centre and mass is uniformly distributed.

The moment of inertia of a system of four rods each of length l and mass m about the axis shown is

Moment of inertia of a cylinder of mass M, length L and radius R about an axis passing through its centre and perpendicular to the axis of the cylinder is I = M ((R^2)/4 + (L^2)/12) . If such a cylinder is to be made for a given mass of a material, the ratio L//R for it to have minimum possible I is :

The moment of inertia of a cube of mass m and side a about one of its edges is equal to

Moment of inertia of a rod of mass m and length l about its one end is I . If one-fourth of its length is cut away, then moment of inertia of the remaining rod about its one end will be

Calculate the moment of inertia of a rod of mass M, and length l about an axis perpendicular to it passing through one of its ends.

The moment of inertia of a uniform rod of length 2l and mass m about an axis xy passing through its centre and inclined at an enable alpha is

The moment of inertia of a ring of mass M and radius R about PQ axis will be

VMC MODULES ENGLISH-ROTATIONAL MOTION -LEVEL - 1
  1. Two uniform identicla rods each of mass M and length l are joined to f...

    Text Solution

    |

  2. Three identical rods, each of mass m and length l, form an equaliteral...

    Text Solution

    |

  3. The moment of inertia of a door of mass m, length 2l and width l about...

    Text Solution

    |

  4. A uniform rod of mass m is bent into the form of a semicircle of radiu...

    Text Solution

    |

  5. A circular disc A of radius r is made from an iron plate of thickness ...

    Text Solution

    |

  6. Two points of a rod move with velocities 3v and v perpendicular to the...

    Text Solution

    |

  7. Find the torque of a alphaforce F=-3hati+hatj+5hatkacting at the point...

    Text Solution

    |

  8. A light rod of length l is pivoted at distance l//4 from the left end ...

    Text Solution

    |

  9. A uniform rod of mass 15 kg is held stationary at 37 degree with the h...

    Text Solution

    |

  10. A uniform bar of mass M and length L is horizontally suspended from th...

    Text Solution

    |

  11. A mass ‘m’ is supported by a massless string wound around a uniform ho...

    Text Solution

    |

  12. A uniform rod of mass m and length L is hinged about one end and can f...

    Text Solution

    |

  13. A slender rod of mass m and length L is pivoted about a horizontal axi...

    Text Solution

    |

  14. A thin rod of mass m and length l is hinged at the lower end to a leve...

    Text Solution

    |

  15. In the pully system shown, if radii of the bigger and smaller pulley a...

    Text Solution

    |

  16. A triangular platge of uniform thickness and densilty ismade to rotate...

    Text Solution

    |

  17. A cord is wrapped on a pulley (disk) of mass M and radius R as shown i...

    Text Solution

    |

  18. A cord wrapped on a pulley (disc) of mass M and radius R as shown in ...

    Text Solution

    |

  19. Statement-I : Magnitude of torque of a force about a given point does ...

    Text Solution

    |

  20. A ladder of length l and mass m is placed against a smooth vertical wa...

    Text Solution

    |