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The centre of a wheel rolling on a plane...

The centre of a wheel rolling on a plane surface moves with a speed `v_(0)`.A particle on th rim of the wheel at the same level as the centre with be moving at speed

A

`sqrt(2)v_(0)`, zero

B

`2v_(0)`, zero

C

`sqrt(2)v_(0), v_(0)^(2)/R`

D

`v_(0),V_(0)^(2)/R`

Text Solution

Verified by Experts

The correct Answer is:
C
Speed `=sqrt(v_(0) + (Romega)^(2)) = sqrt(2) v_(0)`
Acceleration `=omega^(2) R = v_(0)^(2)/R`
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