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A uniform rod of mass m, length l rests ...

A uniform rod of mass `m`, length `l` rests on a smooth horizontal surface. Rod is given a sharp horizontal impulse `p` perpendicular to the rod at a distance `l//4` from the centre. The angular velocity of the rod will be

A

`(3p)/(ml)`

B

`P/(ml)`

C

`P/(2ml)`

D

`(2p)/(ml)`

Text Solution

Verified by Experts

The correct Answer is:
A
Applying `DeltaL` = Angular impulse (about centre of rod)

`I_(cm)omega = P xx l/4`
`omega = (3F)/(ml)`
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