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A thin hoop of weight 500 N and radius 1...

A thin hoop of weight 500 N and radius 1 m rests on a rough inclined plane as shown in the figure. The minimum coefficient of friction needed for this configuration is

A

`1/(3sqrt(3))`

B

`1/sqrt(3)`

C

`1/2`

D

`1/(2sqrt(3))`

Text Solution

Verified by Experts

The correct Answer is:
D
`T + muN = mg sin theta`
`N = mg cos theta`

Net torque about C=0
`therefore TR =muNR` or `T =mu N`
Soliving these three equations we get, `mu=1/(2sqrt(3))`
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