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A uniform rod of mass m and length L lie...

A uniform rod of mass m and length L lies radialy on a disc rotating with angular speed `omega` in a horizontal plane about vertical axis passing thorugh centre of disc. The rod does not slip on the disc and the centre of the rod is at a distance 2L from the centre of the disc. them the kinetic energy of the rod is

A

`1/2m omega^(2)(R^(2) + L^(2)/12)`

B

`1/2 M omega^(2)R^(2)`

C

`1/24 M omega^(2) L^(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

Moment of inertia of the rod w.r.t. the axis through the centre of the disc is (by parallel axis theorem),
`I =(mL^(2))/12 + mR^(2)` K.E. of the rod `=1/2 Iomega^(2) = 1/2 m omega^(2) [R^(2) + L^(2)/12]`
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