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In the reaction. H(2)S+H(2)O(2) rarr S...

In the reaction.
`H_(2)S+H_(2)O_(2) rarr S+2H_(2)O` describes
1. Acidic nature of `H_(2)O_(2)`
2. Reducing nature of `H_(2)O_(2)`
3. Alkaline nature of `H_(2)O_(2)`
4. Oxidizing nature of `H_(2)O_(2)`

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The correct Answer is:
To solve the question regarding the reaction between \( H_2S \) and \( H_2O_2 \) to form sulfur and water, we need to analyze the roles of \( H_2S \) and \( H_2O_2 \) in the reaction. ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is: \[ H_2S + H_2O_2 \rightarrow S + 2H_2O \] Here, \( H_2S \) (hydrogen sulfide) reacts with \( H_2O_2 \) (hydrogen peroxide) to produce sulfur and water. **Hint**: Look at the reactants and products to understand what is being oxidized and reduced. 2. **Determine Oxidation States**: - In \( H_2S \), sulfur has an oxidation state of \(-2\). - In \( H_2O_2 \), the oxidation state of oxygen is \(-1\). - In the product \( S \), sulfur has an oxidation state of \(0\). - In \( H_2O \), oxygen has an oxidation state of \(-2\). **Hint**: Assign oxidation states to each element in the reactants and products to identify changes. 3. **Identify Oxidation and Reduction**: - \( H_2S \) is oxidized to sulfur (oxidation state changes from \(-2\) to \(0\)). - \( H_2O_2 \) is reduced (as it gains electrons) to water (oxidation state of oxygen changes from \(-1\) to \(-2\)). **Hint**: Remember that oxidation involves loss of electrons, while reduction involves gain of electrons. 4. **Identify the Reducing and Oxidizing Agents**: - \( H_2S \) acts as the reducing agent because it donates electrons (is oxidized). - \( H_2O_2 \) acts as the oxidizing agent because it accepts electrons (is reduced). **Hint**: The substance that gets oxidized is the reducing agent, and the one that gets reduced is the oxidizing agent. 5. **Evaluate the Options**: - **Acidic nature of \( H_2O_2 \)**: Not correct, as the reaction does not demonstrate acidity. - **Reducing nature of \( H_2O_2 \)**: Not correct, as \( H_2O_2 \) is not acting as a reducing agent here. - **Alkaline nature of \( H_2O_2 \)**: Not correct, as the reaction does not indicate basicity. - **Oxidizing nature of \( H_2O_2 \)**: Correct, since \( H_2O_2 \) is acting as an oxidizing agent. **Hint**: Analyze each option based on the roles of the reactants in the reaction. ### Conclusion: The correct answer is **4. Oxidizing nature of \( H_2O_2 \)**.

To solve the question regarding the reaction between \( H_2S \) and \( H_2O_2 \) to form sulfur and water, we need to analyze the roles of \( H_2S \) and \( H_2O_2 \) in the reaction. ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is: \[ H_2S + H_2O_2 \rightarrow S + 2H_2O \] ...
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