Reaction of `Br_(2)` with `Na_(2)CO_(3)` in aqueous solution gives sodium bromide and sodium bromate with evolution of gas. The number of sodium bromide molecules formed in the balanced chemical equation is :

Answer

C

Explanation

`Na_(2)CO_(3) overset(H_(2)O)(to) NaOH + CO_(2)` & `Br_(2) + NaOH to NaBr + NaBrO_(3)`
On balancing and simplifying the equation : `3Br_(2) to 5Br^(-) + BrO_(3)^(-) + 3H_(2)O`