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In the section :Na(2)S(2)O(3)+4Cl(2)+5H(...

In the section `:Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`.
the equivalent weight of `Na_(2)S_(2)O_(3)` will be : `(M=` molecular weight of `Na_(2)S_(2)O_(3)`)

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Verified by Experts

The correct Answer is:
B
`5H_(2)O + S_(2)O_(3)^(2-) to 2SO_(4)^(2-) + 8e^(-) + 10H^(+)` `implies` n factor of `S_(2)O_(3)^(-2) =8`
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