Home
Class 12
CHEMISTRY
N(2) + 3H(2) to 2NH(3) In this reaction,...

`N_(2) + 3H_(2) to 2NH_(3)` In this reaction, equivalent weight of `N_(2)` is :

A

`4.67`

B

`28`

C

`14`

D

`2.33`

Text Solution

Verified by Experts

The correct Answer is:
A

`implies E_(N_(2))=28/6 cong4.67`
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise LEVEL (2)|65 Videos
  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|21 Videos
  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|43 Videos
  • STOICHIOMETRY - I

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos
  • STRUCTURE OF ATOM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|7 Videos

Similar Questions

Explore conceptually related problems

N_(2)+3H_(2) to NH_(3)

N_(2)+3H_(2) to NH_(3)

STATEMENT-1: For the reaction NaOH + H_(2)CO_(3) to NaHCO_(3) + H_(2)O equivalent weight of H_(2)CO_(3) is 62. STATEMENT-2: n factor of H_(2)CO_(3) is 1 (in above reaction) and equivalent mass =("Molecular mass")/("n factor")

Assertion (A) : In the reaction, N_(2)+3H_(2) rarr 2NH_(3) , the rate of reaction is different in terms of N_(2), H_(2) and NH_(3) . Reason (R ): The rate of reaction is equal to the rate of disappearance of a reactant or rate of formation of a Product.

In the conversion NH_(2)OH rarr N_(2)O , the equivalent weight of NH_(2)OH will be:

A: In the reaction 2NaOH + H_(3)PO_(4) to Na_(2)HPO_(4) + 2H_(2)O equivalent weight of H_(3)PO_(4) is (M)/(2) where M is its molecular weight. R: "Equivalent weight"= ("molecular weight")/("n-factor")

For N_(2)+3H_(3) hArr 2NH_(3)+"Heat"

N_(2) + 3 H_(2) rarr 2NH_(3) Molecular weight of NH_(3) and N_(2) and x_(1) and x_(2) , respectively. Their equivalent weights are y_(1) and y_(2) , respectively. Then (y_(1) - y_(2))

2NH_(3) to N_(2) + 3H_(2) If at the reaction, 18 mole of H_(2) is produced then find moles of NH_(3) initially taken

In the reaction N_(2)+3H_(2) to 2NH_(3) , the volume ratio of the gases as 1: 3: 2 was

VMC MODULES ENGLISH-STOICHIOMETRY-II-LEVEL (1)
  1. One gas bleaches the colour of flowers by reduction while the other by...

    Text Solution

    |

  2. Which of the following changes requires a reducing agent ?

    Text Solution

    |

  3. N(2) + 3H(2) to 2NH(3) In this reaction, equivalent weight of N(2) is...

    Text Solution

    |

  4. NaHC(2)O(4) is neutralised by NaOH. It can also be oxidised by KMnO(4...

    Text Solution

    |

  5. Cl(2) changes to Cl^(-) in cold NaOH. The equivalent weight of Cl(2)...

    Text Solution

    |

  6. Equivalent weights of KMnO(4) in acidic medium, alkaline medium and n...

    Text Solution

    |

  7. 1 mole of ferric oxalate is oxidised by x mole of MnO(4)^(-) in acidic...

    Text Solution

    |

  8. Which has maximum number of equivalent per mole of the oxidant?

    Text Solution

    |

  9. NH(3) is oxidised to NO by O(2) (air) in basic medium. Number of equ...

    Text Solution

    |

  10. In the following unbalanced redox reaction, Cu(3)P+Cr(2)O(7)^(2-) ra...

    Text Solution

    |

  11. NaHC(2)O(4) is 0.1 M when neutralised with NaOH. Hence, it is ...... w...

    Text Solution

    |

  12. Which of the following is not oxidised by MnO(2) ?

    Text Solution

    |

  13. 100 mL of NaHC(2)O(4) required 50 mL of 0.1M KMnO(4) solution in acid...

    Text Solution

    |

  14. In a titration, H(2)O(2) is oxidised to O(2) by MnO(4)^(-). 24 mL of...

    Text Solution

    |

  15. What is Thiol?

    Text Solution

    |

  16. I^(-) reduces HNO(2) to :

    Text Solution

    |

  17. KMnO(4) oxidises I^(-) to I(2) in acidic medium. The equivalent wei...

    Text Solution

    |

  18. For the reaction 3Br(2)+6OH^(ө)-lt5Br^(ө)+BrO(3)^(ө)+3H(2)O Equiva...

    Text Solution

    |

  19. Moles of KHC(2)O(4) (potassium acid oxalate) required to reduce 100ml...

    Text Solution

    |

  20. Number of electron involved in the reduction of Cr(2)O(7)^(2-) ion in ...

    Text Solution

    |