`1` mole of ferric oxalate is oxidised by `x` mole of `MnO_(4)^(-)` in acidic medium, Hence value of `x` is:

Explanation

To determine the value of \( x \) in the reaction where 1 mole of ferric oxalate is oxidized by \( x \) moles of \( \text{MnO}_4^{-} \) in acidic medium, we can follow these steps:

### Step 1: Write the formula for ferric oxalate
Ferric oxalate is represented as \( \text{Fe}_2(\text{C}_2\text{O}_4)_3 \).

### Step 2: Determine the dissociation of ferric oxalate
When ferric oxalate dissociates in solution, it produces:
\[ \text{Fe}_2(\text{C}_2\text{O}_4)_3 \rightarrow 2 \text{Fe}^{3+} + 3 \text{C}_2\text{O}_4^{2-} \]
Here, each molecule of ferric oxalate produces 2 moles of \( \text{Fe}^{3+} \) ions and 3 moles of oxalate ions \( \text{C}_2\text{O}_4^{2-} \).

### Step 3: Identify the oxidation reaction of oxalate
The oxalate ion \( \text{C}_2\text{O}_4^{2-} \) is oxidized to carbon dioxide:
\[ \text{C}_2\text{O}_4^{2-} \rightarrow 2 \text{CO}_2 + 2 \text{e}^- \]
In this reaction, the oxidation state of carbon increases from +3 to +4.

### Step 4: Determine the total electrons lost
For 3 moles of \( \text{C}_2\text{O}_4^{2-} \) from 1 mole of ferric oxalate:
\[ 3 \text{C}_2\text{O}_4^{2-} \rightarrow 6 \text{CO}_2 + 6 \text{e}^- \]
Thus, the total number of electrons lost is 6.

### Step 5: Determine the reduction reaction of \( \text{MnO}_4^{-} \)
The manganese in \( \text{MnO}_4^{-} \) is reduced from +7 to +2:
\[ \text{MnO}_4^{-} + 8 \text{H}^+ + 5 \text{e}^- \rightarrow \text{Mn}^{2+} + 4 \text{H}_2\text{O} \]
Here, each mole of \( \text{MnO}_4^{-} \) accepts 5 electrons.

### Step 6: Set up the equivalence equation
Since the reaction involves the transfer of electrons, we can equate the total number of electrons lost by the oxalate to the total number of electrons gained by the manganese:
\[ \text{Electrons lost} = \text{Electrons gained} \]
This gives us:
\[ 6 = 5x \]
Where \( x \) is the number of moles of \( \text{MnO}_4^{-} \).

### Step 7: Solve for \( x \)
Rearranging the equation:
\[ x = \frac{6}{5} = 1.2 \]

### Conclusion
The value of \( x \) is \( 1.2 \).

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