Home
Class 12
CHEMISTRY
Which has maximum number of equivalent p...

Which has maximum number of equivalent per mole of the oxidant?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining which oxidant has the maximum number of equivalents per mole, we can follow these steps: ### Step 1: Understand the Concept of Equivalent Weight Equivalent weight is defined as the molecular weight divided by the change in oxidation state. The formula is: \[ \text{Equivalent Weight} = \frac{\text{Molecular Weight}}{\text{Change in Oxidation State}} \] ### Step 2: Identify the Oxidants and Their Molecular Weights The given options are: - A: Zinc (Zn) - B: Silver (Ag) - C: Magnesium (Mg) - D: Iodine (I) We need to find the molecular weights of these elements: - Zinc (Zn) = 65.38 g/mol - Silver (Ag) = 107.87 g/mol - Magnesium (Mg) = 24.31 g/mol - Iodine (I) = 126.90 g/mol ### Step 3: Determine the Change in Oxidation State for Each Oxidant Next, we need to analyze the change in oxidation states for each oxidant: 1. **Zinc (Zn)**: Typically goes from 0 to +2 (Change = 2). 2. **Silver (Ag)**: Typically goes from 0 to +1 (Change = 1). 3. **Magnesium (Mg)**: Typically goes from 0 to +2 (Change = 2). 4. **Iodine (I)**: In the reaction \( IO_3^- \rightarrow I_3^- \): - Oxidation state of I in \( IO_3^- \): Let it be \( x \). \[ x + 3(-2) = -1 \implies x = +5 \] - Oxidation state of I in \( I_3^- \): 0 (as it is in elemental form). - Change in oxidation state = \( 5 - 0 = 5 \). ### Step 4: Calculate the Equivalent Weights Using the formula for equivalent weight, we can calculate: 1. **Zinc (Zn)**: \[ \text{Equivalent Weight} = \frac{65.38}{2} = 32.69 \] 2. **Silver (Ag)**: \[ \text{Equivalent Weight} = \frac{107.87}{1} = 107.87 \] 3. **Magnesium (Mg)**: \[ \text{Equivalent Weight} = \frac{24.31}{2} = 12.155 \] 4. **Iodine (I)**: \[ \text{Equivalent Weight} = \frac{126.90}{5} = 25.38 \] ### Step 5: Compare the Equivalent Weights Now, we compare the equivalent weights calculated: - Zinc: 32.69 - Silver: 107.87 - Magnesium: 12.155 - Iodine: 25.38 ### Conclusion The oxidant with the maximum number of equivalents per mole is **Silver (Ag)** with an equivalent weight of 107.87.

To solve the problem of determining which oxidant has the maximum number of equivalents per mole, we can follow these steps: ### Step 1: Understand the Concept of Equivalent Weight Equivalent weight is defined as the molecular weight divided by the change in oxidation state. The formula is: \[ \text{Equivalent Weight} = \frac{\text{Molecular Weight}}{\text{Change in Oxidation State}} \] ...
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise LEVEL (2)|65 Videos
  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|21 Videos
  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|43 Videos
  • STOICHIOMETRY - I

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos
  • STRUCTURE OF ATOM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|7 Videos

Similar Questions

Explore conceptually related problems

Which has maximum number of atoms:

Which has maximum number of molecules?

Which has maximum number of unpaired e^(-) ?

Which has maximum number of oxo groups ?

Which one has the maximum number of teeth ?

Which has the maximum IE ?

Which has the maximum number of molecules among the following?

Which one has the maximum number of chromosomes?

If A={1,2,3} then the maximum number of equivalence relations on A is

the group which has maximum number of element in Mendeleev's periodic table:

VMC MODULES ENGLISH-STOICHIOMETRY-II-LEVEL (1)
  1. Equivalent weights of KMnO(4) in acidic medium, alkaline medium and n...

    Text Solution

    |

  2. 1 mole of ferric oxalate is oxidised by x mole of MnO(4)^(-) in acidic...

    Text Solution

    |

  3. Which has maximum number of equivalent per mole of the oxidant?

    Text Solution

    |

  4. NH(3) is oxidised to NO by O(2) (air) in basic medium. Number of equ...

    Text Solution

    |

  5. In the following unbalanced redox reaction, Cu(3)P+Cr(2)O(7)^(2-) ra...

    Text Solution

    |

  6. NaHC(2)O(4) is 0.1 M when neutralised with NaOH. Hence, it is ...... w...

    Text Solution

    |

  7. Which of the following is not oxidised by MnO(2) ?

    Text Solution

    |

  8. 100 mL of NaHC(2)O(4) required 50 mL of 0.1M KMnO(4) solution in acid...

    Text Solution

    |

  9. In a titration, H(2)O(2) is oxidised to O(2) by MnO(4)^(-). 24 mL of...

    Text Solution

    |

  10. What is Thiol?

    Text Solution

    |

  11. I^(-) reduces HNO(2) to :

    Text Solution

    |

  12. KMnO(4) oxidises I^(-) to I(2) in acidic medium. The equivalent wei...

    Text Solution

    |

  13. For the reaction 3Br(2)+6OH^(ө)-lt5Br^(ө)+BrO(3)^(ө)+3H(2)O Equiva...

    Text Solution

    |

  14. Moles of KHC(2)O(4) (potassium acid oxalate) required to reduce 100ml...

    Text Solution

    |

  15. Number of electron involved in the reduction of Cr(2)O(7)^(2-) ion in ...

    Text Solution

    |

  16. The number of moles of K(2)Cr(2)O(7) reduced by one mole of Sn^(2+) i...

    Text Solution

    |

  17. In the equation H(2)S+2HNO(3) rarr 2H(2)O+2NO(2)+S The equivalent weig...

    Text Solution

    |

  18. Which of the following is a disproportionation reaction ?

    Text Solution

    |

  19. In the reaction : 3Br(2)+6CO(3)^(2-)+3H(2)Orarr5Br^(-)+BrO(3)^(-)+6H...

    Text Solution

    |

  20. The conversion of sugar C(12)H(22)O(11) to CO(2) is :

    Text Solution

    |