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Moles of KHC(2)O(4) (potassium acid oxa...

Moles of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100ml of 0.02M `KMnO_(4)` in acidic medium (to `Mn^(2+)`) is :

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The correct Answer is:
B
g meq of `KHC_(2)O_(4) = gm eq of KMnO_(4)`
`2xx x=5xx.02xx 100/1000 implies x=0.005` mol. [n factor of `KHC_2O_4` as RA = 2 , of `KMnO_4` = 5]
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