The conversion of sugar `C_(12)H_(22)O_(11) to CO_(2)` is :

Options

A. Oxidation
B. Reduction
C. Neither oxidation nor reduction
D. Both oxidation and reduction

Explanation

To solve the question regarding the conversion of sugar \( C_{12}H_{22}O_{11} \) to \( CO_{2} \), we will follow these steps:

### Step 1: Identify the Reactant and Product
The reactant is sugar, \( C_{12}H_{22}O_{11} \), and the product is carbon dioxide, \( CO_{2} \).

### Step 2: Determine the Oxidation States
- **For the reactant \( C_{12}H_{22}O_{11} \)**:
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.

We can set up the equation for the oxidation state of carbon (C):
\[ 12X + 22(+1) + 11(-2) = 0 \]
Simplifying this:
\[ 12X + 22 - 22 = 0 \implies 12X = 0 \implies X = 0 \]
Thus, the oxidation state of carbon in \( C_{12}H_{22}O_{11} \) is 0.

- **For the product \( CO_{2} \)**:
- The oxidation state of carbon in \( CO_{2} \) can be calculated as follows:
\[ X + 2(-2) = 0 \implies X - 4 = 0 \implies X = +4 \]
Therefore, the oxidation state of carbon in \( CO_{2} \) is +4.

### Step 3: Analyze the Change in Oxidation State
- The change in oxidation state for carbon is from 0 in \( C_{12}H_{22}O_{11} \) to +4 in \( CO_{2} \).
- This indicates that carbon is losing electrons (since its oxidation state is increasing).

### Step 4: Conclusion
Since the oxidation state of carbon is increasing, this process is classified as oxidation. Therefore, the conversion of sugar \( C_{12}H_{22}O_{11} \) to \( CO_{2} \) is an oxidation reaction.

### Final Answer
The conversion of sugar \( C_{12}H_{22}O_{11} \) to \( CO_{2} \) is **oxidation**.

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