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In basic solution CrO4^(2-) oxidises S2O...

In basic solution `CrO_4^(2-)` oxidises `S_2O_3^(2-)` to form `[Cr(OH)_4]^(ɵ)` and `SO_4^(2-)` How many millilitres of 0.154 `M Na_2CrO_4` are required to react with 40.0 " mL of " 0.246 M `Na_2S_2O_3`.

A

200mL

B

156.4mL

C

170.4mL

D

190.4mL

Text Solution

Verified by Experts

The correct Answer is:
C
`40xx0.246xx8=Vxx0.154xx3(Meq.of S_(2)O_(3)^(2-)=Meq.ofCrO_(4)^(2-)`
`V=170.4mL`
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