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The volume of 3M HNO(3) required to oxi...

The volume of 3M `HNO_(3)` required to oxidised 8 g `Fe^(2+)` is
`(HNO_(3) + Fe^(2+) to Fe^(3+) + NO + H_(2)O)`

A

8 Ml

B

16 mL

C

32 mL

D

64 mL

Text Solution

Verified by Experts

The correct Answer is:
B
Meq of `HNO_(3)`=Meq of `Fe^(2+)` or `3xx3xxV=(8)/(56)xx1`
`V=15.87 mL`
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