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In a balanced equation H(2)SO(4)toxHIt...

In a balanced equation
`H_(2)SO_(4)toxHItoH_(2)S+yI_(2)+zH_(2)O`
The values of x,y,z are

A

x=3,y=5,z=2

B

x=4,y=8,z=5

C

x=8,y=4,z=4

D

x=5,y=3,z=4

Text Solution

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The correct Answer is:
To solve the problem of balancing the equation \( H_2SO_4 + xHI \rightarrow H_2S + yI_2 + zH_2O \), we will follow a systematic approach to balance the equation step by step. ### Step 1: Write the Unbalanced Equation We start with the unbalanced equation: \[ H_2SO_4 + xHI \rightarrow H_2S + yI_2 + zH_2O \] ### Step 2: Balance Atoms Other than Hydrogen and Oxygen The atoms we need to focus on are sulfur (S) and iodine (I). - Sulfur: There is 1 sulfur atom on both sides (1 in \( H_2SO_4 \) and 1 in \( H_2S \)), so sulfur is balanced. - Iodine: There is 1 iodine atom in \( HI \) and \( y \) iodine atoms in \( I_2 \). To balance iodine, we need to ensure that the number of iodine atoms on both sides is equal. Since \( I_2 \) contains 2 iodine atoms, we can set \( y = 4 \) (to balance with 8 iodine atoms from \( HI \)). Therefore, we multiply \( HI \) by 8: \[ H_2SO_4 + 8HI \rightarrow H_2S + 4I_2 + zH_2O \] ### Step 3: Balance the Oxygen Atoms Next, we balance the oxygen atoms. - On the left side, \( H_2SO_4 \) has 4 oxygen atoms. - On the right side, each \( H_2O \) has 1 oxygen atom. To balance the oxygen atoms, we set \( z = 4 \) (since \( 4H_2O \) will give us 4 oxygen atoms): \[ H_2SO_4 + 8HI \rightarrow H_2S + 4I_2 + 4H_2O \] ### Step 4: Balance the Hydrogen Atoms Now, we balance the hydrogen atoms. - On the left side, \( H_2SO_4 \) has 2 hydrogen atoms and \( 8HI \) has \( 8 \times 1 = 8 \) hydrogen atoms, giving a total of \( 2 + 8 = 10 \) hydrogen atoms. - On the right side, \( H_2S \) has 2 hydrogen atoms and \( 4H_2O \) has \( 4 \times 2 = 8 \) hydrogen atoms, giving a total of \( 2 + 8 = 10 \) hydrogen atoms. Since both sides have 10 hydrogen atoms, the equation is now balanced. ### Final Balanced Equation The complete balanced equation is: \[ H_2SO_4 + 8HI \rightarrow H_2S + 4I_2 + 4H_2O \] ### Values of x, y, z From the balanced equation, we can now identify the values of \( x, y, z \): - \( x = 8 \) - \( y = 4 \) - \( z = 4 \) ### Final Answer Thus, the values of \( x, y, z \) are: - \( x = 8 \) - \( y = 4 \) - \( z = 4 \) ---

To solve the problem of balancing the equation \( H_2SO_4 + xHI \rightarrow H_2S + yI_2 + zH_2O \), we will follow a systematic approach to balance the equation step by step. ### Step 1: Write the Unbalanced Equation We start with the unbalanced equation: \[ H_2SO_4 + xHI \rightarrow H_2S + yI_2 + zH_2O \] ### Step 2: Balance Atoms Other than Hydrogen and Oxygen The atoms we need to focus on are sulfur (S) and iodine (I). ...
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