What is the oxidation no. Na in NaCl ?

Explanation

To determine the oxidation number of sodium (Na) in sodium chloride (NaCl), we can follow these steps:

### Step 1: Identify the components of the compound
In sodium chloride (NaCl), we have two elements: sodium (Na) and chlorine (Cl).

### Step 2: Assign the oxidation number for chlorine
Chlorine is more electronegative than sodium, and in compounds, it typically has an oxidation state of -1. Therefore, we assign:
- Oxidation number of Cl = -1

### Step 3: Set up the equation for the oxidation numbers
Let the oxidation number of sodium (Na) be represented as \( x \). The formula for sodium chloride can be expressed in terms of oxidation numbers:
\[ \text{Total oxidation number} = (\text{Oxidation number of Na}) + (\text{Oxidation number of Cl}) = 0 \]
This can be written as:
\[ x + (-1) = 0 \]

### Step 4: Solve for the oxidation number of sodium
Now, we can solve the equation:
\[ x - 1 = 0 \]
Adding 1 to both sides gives:
\[ x = +1 \]

### Step 5: Conclusion
Thus, the oxidation number of sodium (Na) in sodium chloride (NaCl) is +1.

### Final Answer:
The oxidation number of Na in NaCl is +1.

---