Calculate the mass of `MnO_(2)`which will be completely oxidises 30 mL of `0. 1M H_(2)C_(2)O_(4)` in acidic medium?

Answer

0.26

Explanation

`C^(3+)_(2) rarr 2C^(4+) + 2e`
`2e + Mn^(4+) rarr Mn^(2+)` [`E_(MnO_(4)) = M/2`]
meq of `MnO_(2) =` meq of `H_(2)C_(2)O_(4)`
`W/E_(MnO_(2)) xx 1000 = 30 xx 0.1 xx2 = 6 `
` W_(MnO_(2)) = 87 xx 6/2xx1000 = 0.261 g`