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For the reaction 2NH(3) to N(2) + 3H(2),...

For the reaction `2NH_(3) to N_(2) + 3H_(2)`,
If `- (d[NH_(3)])/(dt) = k_(!) [NH_(3)], (d[N_(2)])/(dt) = k_(2) [NH_(3)], (d[H_(2)])/(dt) = k_(3) [NH_(3)]` then the relation between `k_(1),k_(2)` and `k_(3)` is

A

`1.5 k_(1) =3k_(2) =k_(3)`

B

`2k_(1) =k_(2)=3k_(3)`

C

`k_(1)=k_(2)=k_(3)`

D

`k_(1)=3k_(2)=2k_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`+(1)/(2) (d[NH_(3)])/(dt) =-(1)/(1) (d[N_(2)])/(dt) =-(1)/(3)(d[H_(2)])/(dt) +(K_(1))/(2)=-K_(2)=(K_(3))/(3)`
`1.5 K_(1) =3K_(2)=K_(3)`
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