Consider the following reaction. The reaction is first order in each direction, with an equilibrium constant of `10^(4)`. For the conversion of chair form to boat form, `e^(-Ea//RT)=4.35xx10^(-8)` at 298 K with pre-exponential factor of `10^(12)s^(-1)`. Apparent rate constant `(k_(A))` at 298 K is :

Options

A. `4.35xx10^(4)s^(-1)`
B. `4.35xx10^(8) s^(-1)`
C. `4.35xx10^(-8)s^(-1)`
D. `4.35xx10^(12) s^(-1)`

Answer

B

Explanation

`k_(B)=Ae^(-E_(a)//RT)=10^(12) xx4.35xx10^(-8)=4.35 xx10^(4)S^(-1)`
Also, equilibrium constant `=(k_(A))/(k_(B))=10^(4) therefore k_(A) =k_(B) xx10^(4)=4.35 xx10^(8) s^(-1)`