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The rate constant for the reaction, 2N(...

The rate constant for the reaction, `2N_(2)O_(5) to 4NO_(2) + O_(2)` is `2 xx 10^(-5) s^(-1)`. If rate of reaction is `1.4 xx 10^(-5) mol L^(-1), s^(-1)` What will be the concentration of `N_(2)O_(5)` in mol `L^(-1)`?

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`r=k [N_(2)O_(5)]" "therefore [N_(2)O_(5)]=(r )/(k) =(2.40xx10^(-5))/(3.0xx10^(-5))0.8" mol L"^(-1)`
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