Which one is correct for `K = A e^(-E_(a)//RT` ?

Options

A. `E_(a)` is energy of activation
B. R is Rydberg constant
C. k is equilibrium constant
D. A is adsorption factor

Explanation

To solve the question regarding the equation \( K = A e^{-\frac{E_a}{RT}} \), we will analyze each component of the equation and the provided options.

### Step-by-Step Solution:

1. **Identify the Components of the Equation**:
The equation \( K = A e^{-\frac{E_a}{RT}} \) is known as the Arrhenius equation, which relates the rate constant \( K \) of a chemical reaction to the temperature \( T \) and the activation energy \( E_a \).

2. **Define Each Variable**:
- \( K \): This is the rate constant of the reaction.
- \( A \): This is known as the pre-exponential factor (or frequency factor), which is a constant that represents the frequency of collisions and the orientation of reactants.
- \( E_a \): This is the activation energy, which is the minimum energy required for a reaction to occur.
- \( R \): This is the universal gas constant, which is approximately \( 8.314 \, \text{J/(mol K)} \).
- \( T \): This is the absolute temperature in Kelvin.

3. **Evaluate the Options**:
- **Option 1**: \( E_a \) is the energy of activation. **Correct**.
- **Option 2**: \( R \) is the Radeberg constant. **Incorrect**; \( R \) is the universal gas constant.
- **Option 3**: \( K \) is the equilibrium constant. **Incorrect**; \( K \) is the rate constant, not the equilibrium constant.
- **Option 4**: \( A \) is the adsorption factor. **Incorrect**; \( A \) is the pre-exponential factor.

4. **Conclusion**:
Based on the analysis, the only correct statement is that \( E_a \) is the energy of activation.

### Final Answer:
The correct option is: **Option 1: \( E_a \) is the energy of activation**.

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