For a first order reaction, (A) `rarr` products, the concentration of A changes from 0.1 M to 0.025 M in 40 minutes. The rate of reaction when the concentration of A is 0.01 M is:

Options

A. `1.73xx10^(-5)M/m` in
B. `3.47xx10^(-4) M//m` in
C. `3.47xx10^(-5) M//m` in
D. `1.73xx10^(-4) M//m` in

Answer

B

Explanation

`k=(2.303)/(40) log""(0.1)/(0.025) rArr k=(0.693)/(20)`
For a first order reaction, rate = k [A], rate `=(0.693)/(20) xx10^(-2) =3.47xx10^(-4)` M/m in.