Lacto bacillus has generation time 60 min. at 300 K and 40 min. at 400 K. Determine activation energy in `(kJ)/(mol)` . (`R = 8.3 J K^ (–1) mol^(–1)` ) `[ log_e (2/3) = - 0.4 ]`

Explanation

(3.98)
In `(k_(2))/(k_(1)) =(Ea)/(R ) [(1)/(T_(1))-(1)/(T_(2))]`
In `((40)/(60)) =(Ea)/(8.3) [(1)/(300)-(1)/(400)] =(Ea)/(8.3) xx (100)/(300xx400)`
Ea = In `((2)/(3)) xx8.3xx1200 =3984" J/mol "=3.984" kJ/mol"`