A first order gas reaction has `k = 1.5 xx 10^(-6) s^(-1)` at `200^(@)C`. If the reaction is allowed to run for `10 h`, what have changed in the Product? What is the half-life of this reaction?

Explanation

(128.33 hr)
`k=1.5 xx10^(-6)s^(-1)`
`kt =" In "(100)/(100-x)`
`rArr" In "(100)/(100-x) =1.5xx10^(-6) s^(-1) xx10xx60xx60 s=0.0054`
`rArr (100)/(100-x) =1.055`
`rArr x=5.25%` reactant is converted into product.
Half-life `=("In "2)/(k) =(0.693)/(1.5xx10^(-6))=462000s =128.33 h`