`2X(g) rarr 3Y(g)+2Z(g)`
`{:("Time (in min)",0,100,200,):}`
`|{:("Partial pressure of X (mm Hg)",800,400,200,),("Assuming ideal gas condition, calculate",,,,):}|`
(a) Order of reaction
(b) Rate constant
( c) Time taken for `75%` completion of reaction
(d) Total pressure when `p_(x) = 700 mm`

Options

A. order of reaction
B. rate constant
C. time taken for 75% completion of reaction
D. total pressure when `p_(x) = 700` mm

Answer

A

Explanation

(i) 1 (ii) `6.93xx10^(-3)" m in"^(-1)` (ii) 200 min
(iv) 950 mm Hg
(a) Partial pressure becomes half of initial in every 100 min, therefore, order = 1.
(b) `kxx100=" In "(800)/(400) =" In "2 rArr k =6.93 xx10^(-3)" m in"^(-1)`
(c ) For 75% reaction, time required `=2xx" half-life"=200` min
(d) `2X(g) rarr 3Y(g) +2Z(g)`
`800-x" "(3)/(2) x" "x`
Total pressure `=800 +(3)/(2) x`
Also `800-x=700 rArr x=100`
`rArr" Total pressure "=800+(3)/(2)xx100=950` mm Hg