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For a first order reaction A rarr P, the...

For a first order reaction `A rarr P`, the temperature `(T)` dependent rate constant `(k)` was found to follow the equation `log k = -2000(1//T) + 6.0`. The pre-exponential factor `A` and the activation energy `E_(a)`, respective, are

A

`1.6xx10^(6)s^(-1) and 9.2" kJ mol"^(-1)`

B

`6.0 s^(-1) and 16.6" kJ mol"^(-1)`

C

`1.0xx10^(6) s^(-1) and 16.6" kJ mol"^(-1)`

D

`1.0xx10^(6)s^(-1) and 38.3" kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`k=AC^(-E_(a)//RT)`
`rArr {:(log K),(10):}={:(log A),(10):}=(Ea)/(2.303 RT) rArr log A =6 rArr A =10^(6) s^(-1) rArr (Ea)/(2.303 R)=200 rArr Ea =2000xx2.303`
`rArr Ea =38.3" kJ/mol"`
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