The weakest oxidizing agent among the following is : [HINT : Refer to Electrochemical series]

Options

A. `O_(3)`
B. `F_(2)`
C. `KMnO_(4)`
D. `Cl_(2)`

Explanation

To determine the weakest oxidizing agent among the given options, we need to refer to the electrochemical series, which lists various substances along with their standard reduction potentials (E°). The higher the reduction potential, the stronger the oxidizing agent. Conversely, the lower the reduction potential, the weaker the oxidizing agent.

### Step-by-Step Solution:

1. **Understand the Concept of Oxidizing Agents**:
An oxidizing agent is a substance that gains electrons in a chemical reaction and is reduced itself while causing the oxidation of another substance. The strength of an oxidizing agent is determined by its standard reduction potential.

2. **List the Given Reduction Potentials**:
- O3 to O2: E° = +2.07 V
- F2 to F-: E° = +2.87 V
- MnO4- to Mn2+: E° = +1.51 V
- Cl2 to Cl-: E° = +1.36 V

3. **Compare the Reduction Potentials**:
From the values listed:
- F2 has the highest reduction potential (+2.87 V), making it the strongest oxidizing agent.
- O3 follows with a reduction potential of +2.07 V.
- MnO4- has a reduction potential of +1.51 V.
- Cl2 has the lowest reduction potential of +1.36 V.

4. **Identify the Weakest Oxidizing Agent**:
Since we are looking for the weakest oxidizing agent, we identify the species with the lowest reduction potential. In this case, Cl2 has the lowest reduction potential of +1.36 V, indicating that it is the weakest oxidizing agent among the options provided.

5. **Conclusion**:
Therefore, the weakest oxidizing agent among the given options is **Cl2**.

### Final Answer:
The weakest oxidizing agent among the following is **Cl2**.