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When a rod of metal A is dipped in an aq...

When a rod of metal A is dipped in an aqueous solution of metal B (concentration of `B^(2+) = 1M`) at `25^(@)`C , the electrode potentials are `A^(2+)` /A = -0.76 Volts, B = +0.343 Volts.

A

A will gradually dissolve

B

B will deposit on A

C

No reaction will occur

D

Water will decompose into `H_2` and `O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`E_(A//A^(2))^(@) + E_(B^(2) + B))^(@)= +ve`
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