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During the electrolysis of aqueous zinc ...

During the electrolysis of aqueous zinc nitrate.

A

Zinc plates out at the cathode

B

Zinc plates out at the anode

C

Hydrogen gas,`H_(2)` , is evolved at the cathode

D

Oxygen gas,`O_(2)` , is evolved at the anode

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The correct Answer is:
### Step-by-Step Solution: 1. **Identify the Electrolyte**: The electrolyte in this case is aqueous zinc nitrate, which can be represented as Zn(NO₃)₂. In solution, it dissociates into zinc ions (Zn²⁺) and nitrate ions (NO₃⁻). 2. **Determine the Ions Present**: In addition to zinc and nitrate ions, water (H₂O) is also present in the solution. However, water does not dissociate significantly into H⁺ and OH⁻ ions. 3. **Identify the Electrodes**: During electrolysis, we have two electrodes: the cathode (where reduction occurs) and the anode (where oxidation occurs). 4. **Reduction at the Cathode**: At the cathode, we need to determine which species will undergo reduction. The two possible candidates are Zn²⁺ and H₂O. We compare their reduction potentials: - The reduction potential for Zn²⁺ + 2e⁻ → Zn is higher than that for the reduction of water (which would produce hydrogen gas). - Therefore, Zn²⁺ will gain electrons and be reduced to solid zinc (Zn). **Reaction at Cathode**: \[ \text{Zn}^{2+} + 2e^- \rightarrow \text{Zn (s)} \] 5. **Oxidation at the Anode**: At the anode, we consider the oxidation of the nitrate ion (NO₃⁻) and water (H₂O). The oxidation potential of water is higher than that of nitrate ions, and since nitrogen in nitrate is already at its maximum oxidation state (+5), it cannot be oxidized further. **Reaction at Anode**: \[ 2\text{H}_2\text{O} \rightarrow \text{O}_2 + 4\text{H}^+ + 4e^- \] 6. **Analyze the Options**: - **Option 1**: Zinc plates out at the cathode. **True** (solid zinc is deposited). - **Option 2**: Zinc plates out at the anode. **False** (oxidation occurs at the anode, not deposition). - **Option 3**: Hydrogen gas (H₂) is evolved at the cathode. **False** (no gas is evolved at the cathode). - **Option 4**: Oxygen gas (O₂) is evolved at the anode. **True** (oxygen is produced at the anode). 7. **Conclusion**: The correct options are 1 and 4. ### Final Answer: The correct statements during the electrolysis of aqueous zinc nitrate are: 1. Zinc plates out at the cathode. 4. Oxygen gas is evolved at the anode.

### Step-by-Step Solution: 1. **Identify the Electrolyte**: The electrolyte in this case is aqueous zinc nitrate, which can be represented as Zn(NO₃)₂. In solution, it dissociates into zinc ions (Zn²⁺) and nitrate ions (NO₃⁻). 2. **Determine the Ions Present**: In addition to zinc and nitrate ions, water (H₂O) is also present in the solution. However, water does not dissociate significantly into H⁺ and OH⁻ ions. 3. **Identify the Electrodes**: During electrolysis, we have two electrodes: the cathode (where reduction occurs) and the anode (where oxidation occurs). ...
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