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Efficiency of the following cell is 84% ...

Efficiency of the following cell is 84%
`A(s)+B_(aq)^(2+) + B(s), DeltaH^(@) = -285KJ`
The standard electrode potential of cell will be.

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To determine the standard electrode potential (E°) of the given electrochemical cell, we will follow these steps: ### Step 1: Understand the relationship between efficiency, ΔG, and ΔH The efficiency of the cell is given as 84%. The relationship between efficiency, Gibbs free energy change (ΔG), and enthalpy change (ΔH) can be expressed as: \[ \text{Efficiency} = \left( \frac{-\Delta G}{\Delta H} \right) \times 100 \] ...
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