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Cr(s)| Cr^(3+)||Fe^(2+)|Fe(s)In the abov...

`Cr(s)| Cr^(3+)||Fe^(2+)|Fe(s)`In the above cell, the value of n in the Nernst equation i.e., `E=E^(@) - (0.059)/(n) log_(10)Q` will be :

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To determine the value of \( n \) in the Nernst equation for the given electrochemical cell \( Cr(s)| Cr^{3+} || Fe^{2+}| Fe(s) \), we need to analyze the half-reactions occurring at the anode and cathode. ### Step-by-Step Solution: 1. **Identify the Anode and Cathode:** - In the cell notation, the anode is on the left side (Cr) and the cathode is on the right side (Fe). - At the anode, oxidation occurs, and at the cathode, reduction occurs. ...
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