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A weak monobasic acid is 5% dissociated ...

A weak monobasic acid is 5% dissociated in 0.01 mol `dm^(-3)` solution. Limiting molar conductivity of acid at infinite dilution is `4xx10^(-2) "ohm"^(-1) m^2 "mol"^(-1)` . What will be the conductivity of 0.05 mol `dm^(-3)` solution of the acid

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`therefore K_(a)=C alpha^(2)=0.01xx(0.05)^(2)= 2.5xx10^(-5)`
`alpha = sqrt(K_(a))/C = 0.0223`
`alpha =(wedge_(m))/(wedge_(m)^(@))`
`wedge_(m)=alpha xxwedge_(m)^(@)=0.0223xx4xx10^(-2)= 89.2xx10^(-5)` `thereforewedge_(m)xx10^(5)= 89.2`
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