The limiting molar conductivities `overset(o)(wedge)` for NaCl, KBr and KCl are 126, 152 and `150 S cm^(2)mol^(-1)` respectively. The `overset(o)(wedge)` for NaBr is:

Options

A. `128Scm^(2) mol^(-1)`
B. `302Scm^(2)mol^(-1)`
C. `278Scm^(2mol^(-1)`
D. `176 S cm^(2)mol^(1)`

Explanation

To find the limiting molar conductivity (λ°) of NaBr using the values provided for NaCl, KBr, and KCl, we can apply Kohlrausch's Law. This law states that the limiting molar conductivity of an electrolyte can be expressed in terms of the limiting molar conductivities of its constituent ions.

### Step-by-Step Solution:

1. **Write down the given values:**
- λ° (NaCl) = 126 S cm² mol⁻¹
- λ° (KBr) = 152 S cm² mol⁻¹
- λ° (KCl) = 150 S cm² mol⁻¹
...