The molar conductivities of `wedge_(NaOAc)^(@)` and `wedge_(HCl)^(@)` at infinite dilution in water at `25^(@)C`are 91.0 and 426.2 S `cm^(2)//mol` respectively. To calculate `wedge_(HOAc)^(@)`, the additional value required is :

Options

A. `wedge_(H_(2)O)^(@)`
B. `wedge_(KCl)^(@)`
C. `wedge_(NaOH)^(@)`
D. `wedge_(NaCl)^(@)`

Explanation

To solve the problem, we will use Kohlrausch's law, which relates the molar conductivities of strong and weak electrolytes at infinite dilution. The formula we will use is:

\[ \lambda^0_{HOAc} = \lambda^0_{NaOAc} + \lambda^0_{HCl} - \lambda^0_{NaCl} \]

Where:
- \(\lambda^0_{HOAc}\) is the molar conductivity of acetic acid at infinite dilution.
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