Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is `100Omega`. The conductivity of this solution
is 1.29 `S m^(-1)` . Resistance of the same cell when filled with 0.2 M of the same solution is `520Omega` . The molar conductivity of 0.2 M solution of the electrolyte will be :

Options

A. `124xx10^(-4) S m^(2) mol^(-1)`
B. `1240xx10^(-4) Sm^(2)mol^(-1)`
C. `1.24xx10^(-4) S m^(2) mol^(-1)`
D. `12.4 xx10^(-4) sm^(2)mol^(-1)`

Explanation

To find the molar conductivity of a 0.2 M solution of the electrolyte, we can follow these steps:

### Step 1: Calculate the Cell Constant (G*)
The cell constant (G*) can be calculated using the formula:
\[ G^* = \text{Conductivity} \times \text{Resistance} \]

Given:
- Conductivity (κ) = 1.29 S/m
...