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Given below are half-cell reaction: Mn...

Given below are half-cell reaction:
`Mn^(2+)+2e^(-) rarr Mn,, E^(@) = -1.18 V`
`2(Mn^(3+)+e^(-) rarr Mn^(2+)),, E^(@) = +1.51 V`
The `E^(@)` for `3Mn^(2+) rarr Mn+2Mn^(3+)` will be:

A

(-)0.33V, The reaction will occur

B

(-2.69V), the reaction will not

C

(-2.69V), the reaction will occur

D

(-.33V), the reaction will not

Text Solution

Verified by Experts

`M n^(2)+2e^(-)to Mn, E^(@)=-1.18V `…..(i)
`2(Mn ^(3+)+e^(-)to Mn^(2+)), E^(@)=+1.51V`…(ii)
Substracting Eq. (ii) From Eq (i), we get
`3M n^(2+)to M n+ 2M n^(3+)`
`E^(@)=-1.18-(+1.51)=-2.69V`
Since, the value og `E^(@)`
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