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Two Faraday of electricity is passed thr...

Two Faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cathode is : (at. mass of Cu = 63.5 amu)

A

0g

B

(63.5g)

C

2g

D

127g

Text Solution

Verified by Experts

`Cu^(2+)+2eto Cu`
`2F i.e 2xx96500 C " deposited " Cu=1 mol =63.5g`
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